For x \in \left(\right. 0 , \textrm{ }\textrm{ } \frac{5 \pi}{2} \left.\right), define f \left(\right. x \left.\right) = \int_{0}^{x} \sqrt{t} sint \textrm{ } dt. Then f has

Engineering

Mathematics

Maxima and Minima

Question

For $x \in (0, \frac{5 π}{2})$ , define $f (x) = \int_{0}^{x} \sqrt{t} sint dt$ . Then f has

local maximum at π and local minimum at 2π

local maximum at π and 2π

local maximum at π and local maximum at 2π

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$f(x) = \int\limits_0^x {\sqrt t \sin tdt} $

$f'(x) = \sqrt x \sin x$

local maximum at π

and local minimum at 2π

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