\frac{tan 35 º}{cot 55 º} + \frac{cot 78 º}{tan 12 º} = ?

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

$\frac{\tan 35 º}{\cot 55 º} + \frac{\cot 78 º}{\tan 12 º} = ?$

None of these

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Given expression $= \frac{\tan 35 º}{\cot (90 º - 35 º)} + \frac{\cot 78 º}{\tan (90 º - 78 º)} = \frac{\tan 35 º}{\tan 35 º} + \frac{\cot 78 º}{\cot 78 º} = (1 + 1) = 2$