From a point P (λ, λ, λ), perpendiculars PQ and PR are drawn respectively on the lines y = x, z = 1 and y = – x, z = – 1. If P is such that QPR is a right angle, then the possible value(s) of λ is(are)
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L1 :
L2 :
L1 L2
Dr's of PR = λ + m, λ – m, λ + 1
Dr's of PR = λ – ℓ, λ – ℓ, λ – 1
– 1 (λ + m) + λ – m + 0 = 0 ⇒ m = 0
λ – ℓ + λ – ℓ + 0 = 0 ⇒ ℓ = λ
PQ PR
(λ – ℓ) (λ + m) + (λ – m) (λ – ℓ) + (λ + 1) (λ – 1) = 0
⇒ λ2 = 1 ⇒ λ = ± 1.
Note: λ = 1 (rejected) as P = Q = (1, 1, 1).