Given E_{\left(Cr\right)^{3 +} / Cr}^{0} = - 0 .74 \textrm{ } V \textrm{ } ; \textrm{ }\textrm{ } E_{MnO_{4}^{-} / \left(Mn\right)^{2 +}}^{0} = 1 .51 \textrm{ } V E_{\left(Cr\right)_{2} O_{7}^{2 -} / \left(Cr\right)^{3 +}}^{0} = 1 .33 \textrm{ } V \textrm{ } ; \textrm{ }\textrm{ } E_{Cl / Cl ¯}^{0} = 1 .36 \textrm{ } V Based on the data given above, strongest oxidising agent will be:

Engineering

Chemistry

Activity or Electrochemical Series

Question

Given

$E_{{Cr}^{3 +} / Cr}^{0} = - 0 .74 V; E_{{MnO}_{4}^{-} / {Mn}^{2 +}}^{0} = 1 .51 V$

$E_{{Cr}_{2} O_{7}^{2 -} / {Cr}^{3 +}}^{0} = 1 .33 V; E_{Cl / Cl ¯}^{0} = 1 .36 V$

Based on the data given above, strongest oxidising agent will be:

Cr³⁺

Cl¯

Mn²⁺

MnO₄¯

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Higher the value of reduction potential data greater is its tendency to get reduced. Hence substance is a better oxidising agent.