HC\equivCH \underset{\left(\right. excess \left.\right)}{\overset{HOCl}{\rightarrow}}A CH3–C\equivCH \underset{\left(\right. excess \left.\right)}{\overset{HOCl}{\rightarrow}} B A & B are respectively

Engineering

Chemistry

Carbocation

Question

HC $\equiv$ CH $\underset{(excess)}{\overset{HOCl}{\to}}$ A
CH₃–C $\equiv$ CH $\underset{(excess)}{\overset{HOCl}{\to}}$ B
A & B are respectively

Cl₂CH–COOH & CH₃CCl₂COOH

Cl₂CH–CHO & CH₃–CCl₂–CHO

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