Engineering
Chemistry
Degree of Freedom Heat Capacities

Question

HClO4 + CH3CN → [X]+ + [Y]–

NOF + ClF3 → [X1]+ + [Y1]–

2ClO3– + SO2 → [X2] + [Y2]–2 

2NOCl + Sn → [X3] + [Y3]

PCl5 + ICl → [X4]++ [Y4]–

JEE Advance
College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Linked Question 1

Choose the incorrect options :

[Y]– and [X4]+ have same hybridisation.

[X2] and [X3] are sp2 hybridised

[Y]– and [Y1]– both are planar

Bond length of [Y3] is greater than [X1]+

Solution
Verified BY
Verified by Zigyan

∵  ∆H > 0

∆S > 0 So entropy driven.

Linked Question 2

What is the hybridisation and shape of [Y1]– ?

sp3d2, square pyramidal

sp2d, trigonal bipyramidal

sp3d2, square planar

sp3d2, octahedral

Solution
Verified BY
Verified by Zigyan

∵  ∆H > 0

∆S > 0 So entropy driven.

Linked Question 3

Choose the correct option for [X2] :

Bond angle is greater than 120°

It is diamagnetic

It has bond angle less than NO2

It is sp3 hybridised

Solution
Verified BY
Verified by Zigyan

∵  ∆H > 0

∆S > 0 So entropy driven.

HClO4 + CH3CN → CH3CNH+ + ClO4–

NOF + ClF3 → NO+ + ClF4–

2ClO3– + SO2 → 2ClO2 + SO42– 

2NOCl + Sn → SnCl2 + 2NO

PCl5 + ICl → [PCl4]+ + [ICl2]–