2CH₂ = CHMgBr + HC $\equiv$ CH $\stackrel{}{\to }$ 2CH₂ = CH₂ + BrMg – C $\equiv$ C – MgBr
  $\left(\frac{2.62}{131}\right)$ mole    $\left(\frac{224}{22400}\right)$ moles
    0.02 mole          0.01 mole
Since, both acidic H of HC$\equiv$CH reacts with CH₂=CHMgBr
So, no. of moles of CH₂=CH₂ produced = 0.02
$\therefore$    Amount in litres = 0.02 × 22400 = 0.448 L