Engineering
Chemistry
Mole and Its Calculation
Question
How many total atoms are present in 5.62 g of Fe2(SO4)3·9H2O ?
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Solution
Molecular mass of Fe2(SO4)3·9H2O
= 56 × 2 + 96 × 3 + 9 × 18
= 562
Mole of Fe2(SO4)3·9H2O = = 10–2 mol
Atoms in Fe2(SO4)3·9H2O
= 2 + 5 × 3 + 9 × 3 = 44
No. of atoms in given sample = 44 × 10–2 NA = 0.44 NA