If 0.01% of a substance undergoing decomposition is consumed in 1 millisecond when the concentration is 0.02 M and in 0.25 millisecond when the concentration is 0.04 M, what is the order of the reaction?

Engineering

Chemistry

Methods of Determination of Order of Reaction

Question

zero

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$\frac{0 .02 \times \frac{0 .01}{100}}{10^{- 3}} = K 0 {.02}^{n}$

$\frac{0 .04 \times \frac{0 .01}{100}}{0 .25 \times 10^{- 3}} = K 0 {.04}^{n}$

2ⁿ = 8
n = 3