If 19th term of a non-zero A.P. is zero, then its (49th term) : (29th term) is

Engineering

Mathematics

Arithmetic Progression and Its Properties

Question

1 : 3

2 : 1

3 : 1

4 : 1

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a + 18d = 0 ⇒ a = –18d

$\frac{t_{49}}{t_{29}} = \frac{a + 48 d}{a + 28 d} = \frac{- 18 d + 48 d}{- 18 d + 28 d}$

$= \frac{30 d}{10 d} = 3$