If 4, x1, x2, x3, 28 are in AP then x3 = ?
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Given AP is 4, x1, x2, x3, 28. Clearly a = 4 and T5 = 28.
Now, T5 = 28 ⇒ a + 4d = 28 ⇒ 4 + 4d = 28 ⇒ 4d = 24 ⇒ d = 6.
x3 = T4 = (a + 3d) = (4 + 3 × 6) = 22.