Foundation
Mathematics Foundation
nth term of AP
Question

If 4, x1, x2, x3, 28 are in AP then x3 = ?

22

Cannot be determined

23

19

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Solution

Given AP is 4, x1, x2, x3, 28. Clearly a = 4 and T5 = 28.

Now, T5 = 28 ⇒ a + 4d = 28 ⇒ 4 + 4d = 28 ⇒ 4d = 24 ⇒ d = 6.

   x3 = T4 = (a + 3d) = (4 + 3 × 6) = 22.