If 52 g of a solute is precipitated from a 400 g 20% solution then percent by mass of the remaining solution is approximately equal to.

Engineering

Chemistry

Concentration Terms

Question

8.04 %

3.02 %

4.02 %

7 %

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First, find the initial mass of solute: 20% of 400 g = $\frac{20}{100} \times 400 = 80$ g. After precipitating 52 g, remaining solute = 80 - 52 = 28 g. The mass of solution decreases by 52 g, so remaining solution mass = 400 - 52 = 348 g. Percent by mass of remaining solute = $\frac{28}{348} \times 100 \approx 8.045$ %, which is approximately 8.04%.

Final answer: 8.04 %