Foundation
Chemistry Foundation
Nuclear Chemistry
Question

If 92X238 liberates an š°-particle then the number of neutrons present in daughter nuclei is -

92

144

146

143

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Solution

When an alpha particle is emitted the mass number of the atom decreases by 4 units and atomic number decreases by 2 units. 
So, 
Number of neutrons in Y = 234 – 90 = 144