Engineering
Mathematics
Introduction to Matrix
Algebra of Matrices
Inverse of a Matrix
Question

If A=[1234], find A–1 by elementary transformation.

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Solution
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Given, A= [1234]
Noe, A + IA
[1234]= [1001]A
R2 → R2 – 3R1
[1202]= [1031]A
R1 → R1 + R2
[1002]= [2131]A
R2 → R2/2
[1001]= [213/21/2]A
A1= [213/21/2]