If A=cosαsinα−sinαcosα, show that A'A = I.
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A=cosαsinα−sinαcosα
on transposing it,
A′=cosα−sinαsinαcosα
Now AA′=cosαsinα−sinαcosαcosα−sinαsinαcosα
AA′=cos2α+sin2α−cosαsinα+sinαcosα−sinαcosα+cosαsinαsin2α+cos2α
AA′=1 00 1
AA' = I