If A and B are matrices of same order then (AB' – BA') is a
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= (B')'(A)' – (A')'B' = BA' – AB' ⋯⋯⋅ {∵ (MN)' = N'M'}
= – (AB' – BA') = – P ....... {∵ (A')' = A}
Hence, (AB – BA') is a skew symmetric matrix.