If A and B are symmetric matrices then AB – BA is a _______.
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∴ A' = A, B' = B
Now, [AB – BA]' = (AB)' – (BA)'
= B'A' – A'B' ⋯⋯⋅ [∵ (AB)' = B'A']
= BA – AB ⋯⋅ {∵ A' = A and B' = B}
= –[AB – BA]
So, [AB – BA] is a skew symmetric matrix.