If A and B are symmetric matrices then BA – 2AB is a _______.
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∴ A' = A, B' = B ⋯⋯(1)
Now, (BA – 2AB)' = (BA)' – (2AB)' = (BA)' – 2(AB)' ⋯ {∵ (kA)' = k(A), k = scalar }
∴ (BA – 2AB)' = A'B' – 2B'A' ⋯ {∵ (AB)' = B'A'}
∴ (BA – 2AB)' = AB – 2BA = – (2BA – AB) ⋯⋅( from (1))
Hence, If A and B are symmetric matrices then
BA – 2AB is neither symmtric nor skew symmetric marix