If A and B are two events such that P(A) > 0 and P(B) ≠ 1, then P(A/B) is equal to (Here A and B are complements of A and B, respectively.)

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Mathematics

Basic Definitions Related to Probability

Addition Theorem on Probability

Conditional Probability

Question

If A and B are two events such that P(A) > 0 and P(B) ≠ 1, then P(A/B) is equal to
(Here A and B are complements of A and B, respectively.)

$1 - P (\frac{A}{B})$

$1 - p (\frac{\bar{A}}{B})$

$\frac{1 - P (A \cup B)}{P (\bar{B})}$

$\frac{P (A)}{P (B)}$

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By conditional probability

$P (\bar{A} / \bar{B}) = \frac{P (\bar{A} \cap \bar{B})}{P (\bar{B})} = \frac{P (\bar{A} \bar{U} \bar{B}) .}{P (\bar{B}) .}$

$= \frac{1 - P (A \cup B)}{P (\bar{B})}$

$P (\bar{A} ∣ \bar{B}) = \frac{1 - P (A \cup B)}{P (\bar{B})}$