Engineering
Mathematics
Exponential and Logarithmic Limits
Question

If a and b be coprime numbers and Limx→π−2(1+tanx)((1+tanx)log(1+tanx2+tanx)+1)=ab then find the minimum value of (a2 + b2).

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Solution

x→π–2,t=tanx→∞

=Limt→∞  (1+t){(1+t)log(1−  12+t) +1}

=Limt→∞  (1+t)[(1+t){−1(2+t)−12(2+t)2− 13(2+t)3−.......}  +  1]

=Limt→∞  (t+1)[{−1+tt+2−(1+t)2(t+2)2−(1+t)3(t+2)3−.......}  +1]

=Limt→∞(t+1){1t+2−(1+t)2(t+2)2−(t+1)3(t+2)3..........}

=Limt→∞  {t+1t+2−(t+1)22(t+2)2−(t+1)23(t+2)3.......}

=1−12=12≡ab

a = k, b = 2k

a2 + b2 = 5k2

a2 + b2 |min. = 5