Engineering
Mathematics
Introduction to Determinants
Question

If a, b, c are all positive and not all equal then the value of the determinant [abcbcacab] is 

0
< 0
> 0
cannot be determined
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Solution
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Let |A|=[abcbcacab]
C1 → C1 + C2 + C3

A=a+b+cbca+b+ccaa+b+cab
=(a+b+c)1bc1ca1ab

R1 → R1 – R2     R2 → R2 – R3
=(a+b+c)0baca0caab1ab
= (a + b + c)[(b – a)(a – b) – (c – a)2]
∴  |A| = – (a + b + c)[(a – b)2 + (c – a)2]
Now, (a – b)2, (c – a)2 > 0 and a + b + c > 0 as a, b, c > 0
∴  |A| < 0 0
Hence, [abcbcacab]<0
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