Engineering
Mathematics
Inverse of a Matrix
Question

If A is an 3 × 3 non-singular matrix such that AA' = A'A and B = A–1A', then BB' equals

I

B–1

(B–1)'

I + B

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Solution

BBT = A–1AT (A–1AT)T

= A–1AT A(A–1)T = A–1AAT(A–1)T

= AT (A–1)T = (A–1A)T = IT = I.