Engineering
Mathematics
Introduction to Determinants
Properties of Determinant
Exponential and Basic Maths questions
Question

If abc ≠ 0 and if abcbcacab=0 then a3+b3+c3abc

– 3

– 2

3
2
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Solution
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abcbcacab
= a(bc – a2) – b(b2 – ac) + c(ab – c2)
= 3abc – a3 – b3 – c3
Given,
abcbcacab=0
So, a3+b3+c3abc=3