Engineering
Mathematics
Conditional Probability
Question

If E and F be events in a sample space such that P(E∪F) = 0.8, P(E∩F) = 0.3 and P(E) = 0.5, then P(F) is

0.6

1

0.8

None

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Solution
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Given, P(E∪F) = 0.8, P(E∪F) = 0.3 and P(E) = 0.5
Since, P(E∪F) = P(E) + P(F) − P(E∩F)
⇒ 0.8 = 0.5 + P(F) − 0.3

⇒ 0.8 = 0.2 + P(F)

⇒ P(F) = 0.6

∴ Option A is correct.

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