Engineering
Mathematics
Introduction to Determinants
Question

If f(x)=sinx1012sinx1012sinx then π2π2f(x) equals 

0

– 1

1

3π2

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Solution
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f(x)=sinx1012sinx1012sinx
Expanding along first column we get,
f(x) = sinx(4sin2x – 1) – 1(2sinx – 0) = 4sin3x – 3sinx
Clearly f(– x) = f(x) ⇒ f is an odd function
Hence π2π2f(x)

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