If f(1) = 1, f '(1) = 3, then the derivative of at x = 1 is

Engineering

Mathematics

Basic Rule of Differentiation

Question

If f(1) = 1, f '(1) = 3, then the derivative of $f (f (f (x))) + {(f (x))}^{2}$ at x = 1 is

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f = f(f(f(x))) +(f(x))²

$\frac{dy}{dx} = f' (f (f (x))) f' (f (x)) f' (x) + 2 f (x) f' (x)$

Put x = 1

$\frac{dy}{dx} = 27 + 6 = 33$