Engineering
Mathematics
Introduction to Determinants
Question

If 6i3i143i1203i=x+iy, then

x = 3, y = 1

x = 1, y = 3

x = 0, y = 3

x = 0, y = 0

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Solution

6i3i143i1203i=x+iy
⇒  6i(3i2 + 3) + 3i(4i + 20) + 1(12 – 60i) = x + iy  ⇒  0 = x + iy
Therefore, x = y = 0
Ans: D

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