Engineering
Physics
Momentum and Energy Conservation for System of Particles
Rolling

Question

If no external force is acting on the system, net linear momentum of the system is conserved. If system is acted upon by some external force, the component of momentum of the system, along which no external force is present or their vector sum is zero, is conserved. If a sharp blow is given to a body its linear momentum changes immediately. Change in angular momentum not only depends on the magnitude of the blow but also on point of application. In the case of symmetrical body we take the axis of rotation through center of the body.

 

A wedge of mass 4m is placed at rest on a smooth horizontal surface. A uniform solid sphere of mass m and radius r is placed at rest on the flat portion of the wedge at the point Q as shown in the figure. A sharp horizontal impulse P is given to the sphere at a point below h = 0.4r from the center of the sphere in vertical plane through centre. The radius of curvature of the curved portion of the wedge is R. Sphere is rolling on a surface without slipping, there should be no relative velocity between the points of contact.

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Linked Question 1

The maximum height to which the center of mass of the sphere will climb on the curved portion of the wedge is

P25m2g

P22m2g

2P25m2g

None of these

Solution

P = 5mv1

12mv2=12(5m)v12+mgh

h=4p210m2g=2p25m2g

Linked Question 2

Kinetic energy of the system when sphere is at the highest point is

P210m

3P25m

P25m

3P210m

Solution

K.E. =12(5m)v12+ 12Icmω2