If P(AUB) = P(A⋂B) then the relation between P(A) and P(B) is..........

Engineering

Mathematics

Conditional Probability

Question

$P(A) = P(B)$

$P(A) < P(B)$

$P(A) > P(B)$

None of these

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$AUB = nA + nB - nA⋂B$
$= nA⋂B$
Thus
$nA + nB = 2nA⋂B$
This is true if A = B.
Hence
$P(AUB) = P(A⋂B)$
Implies P(A) = P(B).

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