If possible values of spin quantum numbers are 3 i.e. - \frac{1}{2}, 0, + \frac{1}{2}. The permissible values of other quantum numbers and rules for filling of orbitals remains unchanged, then number of elements in 4th period is

Engineering

Chemistry

Quantum Numbers

Question

If possible values of spin quantum numbers are 3 i.e. $- \frac{1}{2}$ , 0, $+ \frac{1}{2}$ . The permissible values of other quantum numbers and rules for filling of orbitals remains unchanged, then number of elements in 4th period is

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

number of orbital in 4th period = 4s 3d 4p = 1 + 5 + 3 = 9 orbitals
as spin quantum number are – $\frac{1}{2}$ , 0 , + $\frac{1}{2}$ each
orbital will have 3 electron so
Total 9 × 3 = 27 elements are in the 4th period.]