If tan245º – cos230º = x sin45º cos 45º then x = ?

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

If tan²45º – cos²30º = x sin45º cos 45º then x = ?

$\frac{- 1}{2}$

$\frac{1}{2}$

– 2

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

$x = \frac{\tan^{2} 45 º - \cos^{2} 30 º}{\sin 45 º \cos 45 º} = \frac{1 - {(\frac{\sqrt{3}}{2})}^{2}}{(\frac{1}{\sqrt{2}} \times \frac{1}{\sqrt{2}})} = \frac{1 - \frac{3}{4}}{\frac{1}{2}} = \frac{1}{4} \times \frac{2}{1} = \frac{1}{2}$