If the angles A, B and C of a triangle are in an arithmetic progression and if a, b and c denote the lengths of the sides opposite to A, B and C respectively, then the value of the expression , is
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= 2 sin(A + C) = 2 sin ( – B) = 2 sin B
As A + B + C = and A + C = 2B B = 60°
E = 2 sin 60° = Ans.
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