Engineering
Physics
Electromagnetic Waves
Question

If the magnetic field in a plane electromagnetic wave is given by B→=3×10−8sin(1.6×103x+48×1010t)j^T, then what will be expression for electric field?

E→=(9sin(1.6×103x+48×1010t)k^V/m)

E→=(60sin(1.6×103x+48×1010t)k^V/m)

E→=(3×10−8sin(1.6×103x+48×1010t)i^V/m)

E→=(3×10−8sin(1.6×103x+48×1010t)j^V/m)

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Solution

E0B0=C (speed of light in vacuum)

E0 = B0C = 3 × 10–8 × 3 × 108

= 9 N/C

So E = 9sin (1.6 × 103 x + 48 × 1010 t)