If the probability for A to fail in an examination is 0.8 and that for B is 0.7, then the probability that atleast one of A or B fails, is

Engineering

Mathematics

Conditional Probability

Question

$\frac{4}{25}$

$\frac{6}{25}$

$\frac{43}{50}$

$\frac{47}{50}$

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P(A) = 0.8 P(B) = 0.7

P(A∩B) = 0.56

∴ P(AUB) = P(A) + P(B) – P(A∩B)

= 0.94

$= \frac{47}{50}$

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