If the tangent at (1, 7) to the curve x2 = y – 6 touches the circle x2 + y2 + 16x + 12y + c = 0 then the value of c is
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x2 = y – 6
2x = y'
y' at (1, 7) = 2
= 2
⇒ k – 7 = 2h – 2
⇒ 2h – k = –5 …….(i)
Now,
⇒ 2k + 12 = – h – 8
⇒ h + 2k = –20 ........(ii)
from (i) and (ii)
h = –6 , k = –7
x2 + y2 + 16x + 12 y + c = 0 ⇒ 36 + 49 – 96 – 84 + c = 0 ⇒ c = 95.