If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium ions, m and n, respectively, are
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In ccp lattice:
Number of O atoms → 4
Number of Octahedral voids → 4
Number of tetrahedral voids → 8
Number of Al3+ = 4 × m
Number of Mg2+ = 8 × n
Due to charge neutrality = 0
4(-2) + 4m (+3) + 8n (+2) = 0