Engineering
Mathematics
Introduction to Determinants
Question

If three points (x1, y1), (x2, y2) and (x3, y3) lie on the same line, prove that y2y3x2x3+y3y1x3x1+y1y2x1x2=0.

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Solution
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(x1, y1), (x2, y2), (x3, y3) lie on same line
To prove
y2y3x2x3+y3y1x3x1+y1y2x1x2=0
Let the line be y = mx + c
(x1, y1) is on the line
⇒  y = mx1 + c
(x2, y2) is on the line
⇒  y2 = mx2 + c
(x3, y3) is on the line
⇒  y3 = mx3 + c
LHS
y2y3x2x3+y3y1x3x1+y1y2x1x2
(mx2+cmx3c)x2x3+(mx3+cmx1c)x1x3+(mx1+cmx2c)(x1x2)
m[(x2x3)x2x3+(x3x1)x3x2+(x1x2)x1x2]
m[(x1x2x1x3)x1x2x3+(x2x3x2x1)x1x2x3+(x1x3x2x3)x1x2x3]
m(0x1x2x3)0RHS
⇒  LHS = RHS
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