If x, y, z are in A.P. and tan–1x, tan–1y and tan–1z are also in A.P., then :
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2y = x + z [ x, y, z are in A.P.]
2tan–1y = tan–1x + tan–1z (tan–1x, tan–1y, tan–1z in A.P.)
(x + z = 2y)
1 – y2 = 1 – xz
y2 = xz
x, y, z are in G.P. and A.P. both.
Hence x = y = z.