Engineering
Mathematics
Geometry of Complex Number
Question

If z1 and z2 are complex numbers satisfying the equations |z|=5  and  |z−2(1+i)z|=1  then find |z1 – z2|.

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Solution

∵|z−2(1+i)z|=1

⇒|z−2(1+i)|  =  |z|  =  |z−0|

∴ z is perpendicular bisectors of line joining (2,2) and (0, 0) where (0, 0) is centre of |z|=5 with radius 5.

Clearly OM = 1 and OA = 5

∴ AM = 2

∴ AB = |z1 – z2| = 4