If 2 sin 2 \theta = \sqrt{3} then θ = ?

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

If $2 \sin 2 θ = \sqrt{3}$ then θ = ?

60º

30º

90º

45º

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$2 \sin 2 θ = \sqrt{3} \Rightarrow \sin 2 θ = \frac{\sqrt{3}}{2} = \sin 60 º \Rightarrow 2 θ = 60 º \Rightarrow θ = 30 º$