If cosecθ = \sqrt{10} then sec θ = ?

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

If $cosecθ = \sqrt{10}$ then sec θ = ?

$\frac{\sqrt{10}}{3}$

$\frac{2}{\sqrt{10}}$

$\frac{1}{\sqrt{10}}$

$\frac{3}{\sqrt{10}}$

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