If \sqrt{3} tan 2 \theta - 3 = 0 then θ = ?

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

If $\sqrt{3} \tan 2 θ - 3 = 0$ then θ = ?

30º

60º

45º

15º

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$\sqrt{3} \tan 2 θ = 3 \Rightarrow \tan 2 θ = \frac{3}{\sqrt{3}} = \sqrt{3} = \tan 60 º \Rightarrow 2 θ = 60 º \Rightarrow θ = 30 º$

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