If tanθ = \frac{a}{b} then \frac{\left(\right. cosθ + sinθ \left.\right)}{\left(\right. cosθ

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

If $tanθ = \frac{a}{b}$ then $\frac{(cosθ + sinθ)}{(cosθ - sinθ)} = ?$

$\frac{b + a}{b - c}$

$\frac{b - a}{b + c}$

$\frac{a - b}{a + b}$

$\frac{a + b}{a - b}$

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If $tanθ = \frac{a}{b}$ then $\frac{(cosθ + sinθ)}{(cosθ - sinθ)} = \frac{1 + tanθ}{1 - tanθ} = \frac{1 + a / b}{1 - a / b}$