In a class of 30 students, 10 take mathematics, 15 take physics and 10 take neither. The number of students who take both mathematics and physics is
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n(A ⋃ B) = n(A) + n(B) – n (A ⋂ B)
20 = 10 + 15 – n(A ⋂ B) or n(A ⋂ B) = 5