In a double slit pattern (λ = 6000 Å), the first order and tenth order maxima fall at 13.00 mm and 15.25 mm from a particular reference point. If λ is changed to 5400Å. The position of tenth order fringe is 5N mm, other arrangement remaining the same. Find N.

Engineering

Physics

Intereference New

Question

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

$a + \frac{λD}{d} = 13 .00$

$a + \frac{10 λD}{d} = 15 .25$

$\frac{λD}{d} = \frac{1}{4} mm$

a = 12.75

$\frac{10 λ' D}{d} = 10 \times 5400 \times \frac{1}{4 \times 6000 \times 10} = 2 .25 mm$

Position = 12.75 + 2.25 = 15 mm