In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of the emitted radiation is λ. If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be

Engineering

Physics

Radiation

Question

$\frac{25}{16} λ$

$\frac{27}{20} λ$

$\frac{16}{25} λ$

$\frac{20}{27} λ$

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For M → L steel

$\frac{1}{λ} = K (\frac{1}{2^{2}} - \frac{1}{3^{2}}) = \frac{K \times 5}{36}$

For N → L

$\frac{1}{λ'} = K (\frac{1}{2^{2}} - \frac{1}{4^{2}}) = \frac{K \times 3}{16}$

$λ' = \frac{20}{27} λ$