In a simultaneous throw of two dice what is the probability of getting a doublet ?

Engineering

Mathematics

Conditional Probability

Question

$\frac{1}{6}$

$\frac{1}{4}$

$\frac{3}{4}$

$\frac{2}{3}$

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Total number of possibilities = 36
Number of doublet = 6
Thus, probability = $\frac{6}{36} = \frac{1}{6}$

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