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Question
In a survey of 45 houses, it was found that 25 have cars and 30 have two-wheelers. How many have both ?
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Solution
n(A∪B) = n(A) + n(B) − n(A∩B)
45 = 25 + 30 − n(A∩B)
⇒ n(A∩B) = 10