In an experiment the refractive index of glass was measured to be 1.45, 1.56, 1.54, 1.44, 1.54 and 1.53. Find percentage error.

Engineering

Physics

Errors

Question

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$µ_{mean} = \frac{1 .45 + 1 .56 + 1 .54 + 1 .44 + 1 .54 + 1 .53}{6}$

= 1.51

$Δ µ_{m} = \frac{| Δ µ_{1} | + | Δ µ_{2} | + | Δ µ_{3} | + | Δ µ_{4} | + | Δ µ_{5} | + | Δ µ_{6} |}{6}$

$Δ µ_{m} = \frac{0 .06 + 0 .05 + 0 .03 + 0 .07 + 0 .03 + 0 .02}{6}$

= 0.0433 ≈ 0.04

$Fractional error = \frac{Δ µ_{mean}}{µ_{mean}} = \frac{0 .04}{1 .51} = 0 .03$

$∴$ % Error = 3%