In an I.C. engine, a gas is undergoing a cyclic process as shown in P-V diagram. If the engine completes 5 cycles in a second, then the average power of the engine is x × 105W. Then value of x is :

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Work done by the gas in one cycle
= Area under P – V graph
= 20 kJ
In 1 sec., 5 cycles are completed
So, Work done in 1 sec.
= 5 × 20 kJ = 100 kW.